0=8x^2+12x-4896

Solution for 0=8x^2+12x-4896 equation:

0=8x^2+12x-4896

We move all terms to the left:

0-(8x^2+12x-4896)=0

We add all the numbers together, and all the variables

-(8x^2+12x-4896)=0

We get rid of parentheses

-8x^2-12x+4896=0

a = -8; b = -12; c = +4896;
Δ = b2-4ac
Δ = -122-4·(-8)·4896
Δ = 156816
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{156816}=396$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-396}{2*-8}=\frac{-384}{-16}
=+24
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+396}{2*-8}=\frac{408}{-16}
=-25+1/2
$